https://codeforces.com/contest/1287/submission/68341470. Currently, I am a student at Daffodil International University. https://codeforces.com/contest/1287/submission/68427357. 1 D: LCC? I did almost the same thing but by optimizing the recursion. Problem link A solution in c++ . If you want code you can ping me. Ask Question Asked 4 years, 8 months ago. codeforces 1287B. So you can at least change it to 303 Squadron, Can someone point out what's wrong in my DP approach to C-Garlands? Then, if this function got task to give answer about certain subtree, we can feed it with all subtrees of childs. (anology to RR), if $$t_i = 1$$$then condition $$a_{x_i} \geq p_{x_i}\;and\; a_{x_i+1} \geq p_{x_i+1}$$$ should be false. num1 means the total odd number in range of 1-n and num0 is the even.ï¼num1 equals to ceil(n/2) and num0 equals to floor(n/2) ) The time complexity is O(nÂ³ï¼, Secondly, since the number of even and odd used is sure in the range 1-i( if you use j even numbers, the number of odds is certainly i-j) , you can just use dp[i][j][0/1] where j means the number of evens in range 1-i (or that of odds if you like), and the dp dynamic formula will not change a lot. My submission https://codeforces.com/problemset/submission/1287/68273741, even i am getting TLE on test case 10 for 68349376, You can use combination and use map for count the same string. E.g. Wow, I have completely different solution to D. Mine is in fact much more complicated and fact that time of collision when both particles go facing each other is strictly less than time of collision when they go in the same direction is in fact crucial to my solution, while model solution just don't care. Help needed from participants with rating up to 1500, Help me to find out the right approach of this code, The 'science' of training in competitive programming, https://codeforces.com/contest/1287/submission/68254686, https://codeforces.com/contest/1287/submission/68316351, https://codeforces.com/contest/1287/submission/68316468, https://codeforces.com/contest/1287/submission/68341470, https://codeforces.com/problemset/submission/1287/68273741, https://codeforces.com/contest/1287/submission/68353515, https://codeforces.com/contest/1287/submission/68427357, concatenate them to have nice 1,2,3...n form (all nodes except current node). How to update anaconda. The explanation is that if you consider the value in the range 1~i with j odds and k evens used and the current one being odd, you need to think about the values, which you have calculated, in the range 1~(i-1), with (j-1) odds and k evens used since it is the only legal transition state to the current state. I have a few doubts. [Beta] Harwest â Git wrap your submissions this Christmas! My (maybe simpler) solution for 1286D - LCC: The main idea is still sorting all the collisions and calculate the probability that first $$i$$$-th and $$(i + 1)$$$-th will occur. [codeforces 1380B] Universal Solution 剪刀石头布(将所有情况聚集的构造) [codeforces 1380C] Create The Teams 自大到小排序后再分组. May Batch Will Graduate on July 15th, 2020. We just insert it at place we need to satisfy restriction about number of vertices in subtree. Then, the transition is not difficult. Codeforces constantly develops and we plan to improve the platform to give the participants the opportunity to organize their own contests, filling the project with learning content, developing Codeforces as a training and learning 1), problem: (A) Points on Line solution garakchy Algorithm, Programming and some problem solutions. We conduct about 4-6 regular contests per month, each contest consists of about 5 problems. Anything else missing in the Div2 C taglist? Here is my code. All of them has answer in the form 1,2,3...n. Also, keep along with it original indices of vertices. After we add this to the sum, x now becomes new l. You need to calculate number of arrays $$a$$$of length $$n$$$ of numbers 0 to 9 such that some configurations banned. Imagine a vector, 0 2 0 4 5 0 Now, the answer is 1 2 6 4 5 3 that is 2 but your program will give 3 because of above statement. For most of the problems there will be editorial in Codeforces. When we connect two components with some event of type $$0$$$, it's a few casework to figure out the resulting component's range of special positions. My O(nlogn) solution for Div2D/DIV1B Insert all numbers from 1 to n in a order-statistics tree. Previous Previous post: codeforces solution 271A – Beautiful Year Next Next post: codeforces solution 486A – Calculating Function Leave a Reply Cancel reply Word Capitalization2 2 Problem 2B. Pros. I managed to find 8 different strings with same answer, namely: abaabbabaabaabbabbabaabbab abaabbabbabaabbabaabaabbab abbabaabaabbabaabbabbabaab abbabaabbabbabaabaabbabaab baababbaabaababbabbaababba baababbabbaababbaabaababba babbaabaababbaababbabbaaba babbaababbabbaabaababbaaba But in the official testcases my solution never encountered more than two candidates for each half. :). I'm not able to understand your concept? There is some sorting involved, that's why $$O(n\log{n})$$$. HyperX sells direct in the listed countries. Add on top of that open hash table with square steps and you're blazing fast 68356690. So u should try to change set to 3 if conditions. If true. Time limit per test 1 second. Corresponding childs are enclosed in brackets again. Codeforces - Register new account - submit example (http://codeforces.com/problemset/problem/4/A) And whether the previous one you choose is odd or even depends on their values. Could you, please, briefly explain why in the third example the correct answer is 150902884? In order to get the answer, we look at the vector corresponding to the root of our tree: there, all vertices are listed in increasing order of values. We want to calculate the probability that the $$i$$$-th of these collisions occur first. I get TLE with both fast zeta-transform 68330755 ($$\mathcal{O}(2^{n} n^{2} \log n)$$$)Â and the $$3^{n}$$$approach 68330966, and AC only with fast randomised binary zeta-transform 68331478 ($$\mathcal{O}(2^{n} nk \log n)$$$ where probability of success is polynomial in $$(1 - 2^{-k})$$$). Then, apply expectation value formula by definition and you'll get answer. My Review about Scaler academy. One can prove that if there is a solution, then there is alsoa It's just ban all collisions. But I am unable to understand how to do query of type 3 . A. Watermelon. Then, when you'll write this thing, find out how to add ban online and update answer fast. Can somebody explain it please? https://codeforces.com/contest/1287/submission/68316351 this is O(k(n^2)log(n)) solution.But still getting TLE. Statement is following: you're given $$n,\;m,\; 0 \leq p_i \leq 10,\;0\leq t_i\leq 2,\;0\leq x_i\leq n-1$$$, it is number of particles, number of bans, probability 0 to 10, type of ban, and position of ban. If you have trouble with probability understanding, for n particles there is $$100^n$$$variations, and particle $$i$$$ fly to the right in $$p_i$$$cases and to the left in $$100-p_i$$$ cases, then you may count how many of configurations among $$100^n$$$is correct (taking bans into consideration), then divide the number by $$100^n$$$ and it is probability. 2, based on Zed Code Competition), which will be held on Dec/11/2020 17:35 (Moscow time).. We want to offer you to solve 6 problems taken from the Zed Code Competition 2020, which was held as part of the Adapt by Zed conference powered by EPAM Systems.. This is because the value of odd, even, the level is the same for both paths but since the path with greater value is calculated first, your dp[odd][even][level] may contain value which is not minimal for those value of odd, even and you are returning that non-minimal value without checking. To make things clear, if there are n particles, then potentially you may have 3*n elements in this list. Streets of Torzhok are so narrow that students have to go ..._vertex has two integers written on it, and the integers written on vertex i Codeforces. According to your code, 1 2 6 4 is equivalent to 6 2 1 4, so if the program went on path 6 2 1 4 before 1 2 6 4, it will give the wrong answer. Could anyone show me how to solve it? for problem B, why does 68349376 give TLE inspite of being n^2logn? So we just need to narrow the range and recalculate the probability. CODEFORCE } return 1; } To compile c program in linux replace g++ with gcc in the command rest all the steps are same also for running. Thank you for your reply. I am no expert but that's all I could think of. GitHub Gist: instantly share code, notes, and snippets. 2) Editorial. Hi Code forces!. Basically, ($$123^{-1}$$$mod 998244353) is 32463231, since 32463231*123 mod 998244353 equals to 1. s = s + k creates a new string equal to s + k which takes $$O(|s| + |k|)$$$ time and memory and then assigns it to s, s += k works in $$O(|k|)$$$(according to c++ standard might also work in $$O(|s| + |k|)$$$, but that would be ridiculous to implement it this way). yeah,sorry for the complexity,but what should i do to optimise then?should i write using ifs? It is maintained by a group of competitive programmers from ITMO University led by Mikhail Mirzayanov. So you can evaluate all symbols in parallel using bitwise operations. Similarly, for a even number, it is " dp[i][j][k][0]=min(dp[i-1][j][k-1][0], dp[i-1][j][k-1][1]+1) ". You don't need the Next() function in your code. Present view controller with animation swift. Why is time limit getting exceeded on test case 10? Please someone answer why my code for div2 B 68280267 is getting TLE , though my complexity is O(n^2(k+log(n)). We iterate through them; to find the probability that a particular collision comes first, we get the probability before the ban, ban the collision by changing the $$ban$$$value in the leaf node corresponding to the left particle, then get the probability after the ban. could you explain the second and third point more clearly,i saw your code it was quite simple so could you help it more? My solution involves some dp on subtrees. Your problem is in check function. Just notice you have Luftwaffe in your username. (anology to LL), if $$t_i = 2$$$ then condition $$a_{x_i} < p_{x_i}\;and\; a_{x_i+1} \geq p_{x_i+1}$$$should be false. So, for particles 5,6 we can do at once: LL â allow to collide, RR â ban, RL â allow for example (I don't care here about possibility of this case, but we can ban RR only). I have some problems with understanding of the LCC problem. Could someone explain the approach for doing div-1 question A though dp? But, it turns out, it's describing same approach. So both two above formulas should be considered. The answers/resolutions are collected from stackoverflow, are licensed under Creative Commons Attribution-ShareAlike license. (1), (2) is right. 1: Contest URL: Contest Title: Problem URL: Problem ID: Problem Title: Solved Users: Time Limit: Memory Limit: Tags => Correspoding parts to each child is enclosed into brackets. count all odd space(where starting and ending is odd) and even space(where starting and ending is even) sort both odd and even array. 68267302 Why it works? :). For this task, even PyPy doesn't help. Why is order[v] guaranteed to be listed in increasing order of values even before inserting the element in c[v]th position? Solution to Codeforcess Div 3. But I am still confused. To be honest, when I read the problem description I expected the solution to be a real number. Codeforces Round #655 (Div. I have experiences of working with a team in online problem-solving judge sites, Example: Uva, Codeforces, Hackarranks etc. Lets first denotes the types of two protons colliding: $$0$$$ â moving toward each other, $$1$$$â both moving to the left and $$2$$$ â both moving to the right. Since 2013, Codeforces claims to surpass Topcoder in terms of active contestants. could you explain it once again. by using counting sort, we receive to O(n) solution. I solved Div1D(LCC) with Segment tree, but I see one of the tags for it is matrices. it's interesting that the vast majority of div1 folks just decided to use dp in div1_a. Now, if we allow highest time of collision: there are two cases: nothing collide, or one or more collide at the same time the highest time of collision. The trick is, that you may change single unit segment to ban some of combinations, and recalculate probability of whole segment in log(n). If it is okay with you, can you please clarify some of my doubts ? i did not get it ? If it is an odd, the formula is " dp[i][j][k][1]=min(dp[i-1][j-1][k][0]+1, dp[i-1][j-1][k][1]) ". These three loops will run over some unordered triplets more than once. if $$t_i = 0$$$then condition $$a_{x_i} < p_{x_i}\;and\; a_{x_i+1} < p_{x_i+1}$$$ should be false. Can you please further explain it. Here is what I understood so far. I still can't get it. Html new line   Add a Line Break in HTML - Tutorial, More "Try it Yourself" examples below. I like to build up algorithms in an efficient and optimized way and write clean code. answer on this test is 1 according to accepted solutions: 68650401 , 68385020 , 69983917 , but I don't know which permutation gives us this result? As of 2018, it has over 600,000 registered users. Codeforces Round #153 (Div. Similarly, probability of second highest time is probability that it's allowed (and above) minus probability of highest time collision allowed (and above). Secondly, in order to get a correct value, we need to initialize the value of dp array correctly. Can anyone please help me by telling that what am I doing wrong in my DP approach for problem C Garland.Click here to see my code. sorry if my explanation wasn't very clear. dp[i][j][k][1]=min(dp[i-1][j-1][k][0]+1, dp[i-1][j-1][k][1]) " Could you please tell me the significance of adding 1 to dp[i-1][j-1][k][0] in transition function ? *has extra registration Rails joins. I still have no idea why 1st submission got accepted while 2nd one was not accepted. Because temp=temp+symbol performs copying of string. Download submission. Codeforces Problem Statement Jumper. Hi All! Second point is to concatenate them in similar form. Agm-info-window close event. Author Scrap W Daily installs 0 Total installs 36 Ratings 0 0 0 Version 1.1 Created 2019 … 2)（题解）A. We find all possible collisions and sort them by the time of collision (represented in my collision tuple as the fraction $$\dfrac d v$$$, i.e. Here's an updated list of most popular Codeforces alternatives. For $$99/123$$$, just multiply them together and mod the result by $$998244353$$$. When you calculate dp[i-1][j-1][k][0],you put an even number on position i-1. Previous Previous post: codeforces solution 580A – Kefa and First Steps Next Next post: codeforces solution 451A – Game With Sticks Leave a Reply Cancel reply So, probability that you have highest time collision is: probability of highest time of collision allowed minus probability of no collision allowed. if (a[i] % 2 || !a[i]) dp[i][j][1] = min(dp[i â 1][j][0] + 1, dp[i â 1][j][1]); if (a[i] % 2 == 0 && j) dp[i][j][0] = min(dp[i â 1][j â 1][0], dp[i â 1][j â 1][1] + 1); The above code is a sanp from a garland problem, please can anyone explain what does i,j and 1 mean, i'm not able to get it with any comment, time complexity of question Dic2-C is O(n) not O(nlogn). The combined segment inherits the $$ban$$$ value of the right segment. Would anyone please help me with this ? As it was mentioned in comment above, you should perform appending char to a string with S+=symbol, not S=S+symbol. Sunday, July 20, 2014 Codeforces Round #153 (Div. can anyone point out the mistake for solution of problem-Garland my solution is this... Looks like, even though according announcement 1286E - Fedya the Potter Strikes Back will accept any answer by modulo 2^64, current checker wants full integer or there is some bug with comparison. For a vertex $$v$$$, glue together all vectors of its children and insert $$v$$$ into it on the $$c_v$$$-th position. ( codeforces 369篇 atcoder 138篇 kuangbin带你飞 4篇 操作系统 1篇 算法竞赛入门经典（第2版）第3章 数组和字符串 18篇 算法竞赛入门经典（第2版）第4章 函数和递归 17篇 NOIP 提高组 复赛 76篇 NOIP 提高 … Replace it with simple if's and your solution should pass. Since I struggled with understanding the solution for 1287F - LCC too, here's my sample code and explanation that may help others: Each segment (including the "segment" consisting of a single particle) is represented by a tuple of 5 values, $$(ll, lr, rl, rr, ban)$$$. Read tutorials, posts, and insights from top Codeforces experts and developers for free. Well it's already stated in the statement that you need to print the answer as $$P . Welcome to Algorithmist Q, where you can ask questions about algorithms, problems, and competitive programming! I have been working on c++ and Java for 2 Years continuously. The probability we want is then$$$p_{before} - p_{after}$$. Codeforces is a website that hosts competitive programming contests. thanks in advance. For example, if we have three answers: (1,2,3,4), (1,2), (1,2,3,4,5,6), then we can get (1,2,3,4),(5,6),(7,8,9,10,11,12). With the greedy solution you also have to consider special cases (ie. For instance, if the answer is 99/123, what should I output? Codeforces is a Russian website dedicated to competitive programming. But I'm too lazy to describe it cause it's long x_0. The tag is useful for writing addresses or poems. HackerRank, Geeksforgeeks and HackerEarth are some of the top options that you should consider out of 24 available alternatives of Codeforces. For most of the problems there will be editorial in Codeforces. So, you represent whole array of particles as array of unit segments with 4 masks, and using segmented tree you may find probability of whole segment. What you can do is remove that line and check all possible conditions but I tried it and it's resulting in TLE. Could someone explain the approach for 1287D - Numbers on Tree? There's 1 more issue when you are setting a[level] to odd, you are not reverting it back to 0. My code seems pretty okay to me, however it is not passing testcas... Stack Overflow. use (temp +=) instead of temp = temp + newchar when appending a char to a string, Try hardcoding instead of the function nex, might help, Never try to access a value from map by operator[] if you're not sure it exists there. insert current node at exact position, and increment all numbers above. If we only take collisions of type$$$0$$into account, a consecutive segments where every protons have collisions with its neighbors, can only accept patterns like this:$$$Â«Â«Â«...Â»Â»Â»$$. So, not surprising that you didn't understand it. Codeforces #172 Tutorial xiaodao Contents 1 Problem 2A. https://codeforces.com/contest/1287/submission/68316468. Definition and Usage. This is an implementation based problem. That would be appreciated. (anology to RL). You’ll find me almost all technological medium by @jinnatul programming. distance over relative velocity). The original "Set" game can be viewed as "Hyperset" with k = 4 k = 4. The editorial says that the answer for the mask is the probability that none of the$$$X$collisions do not occur and the extremes move in the direction of the mask. Due to the expense of combining operations and frequent querying for the entire segment tree, the segment tree code, based on the type described by this blog entry, has been modified to always round up to the nearest power of two for the internal size. We ban pairs of consecutive particles to collide in exact configuration. Great, just learnt a better way of doing. u need to keep track to previous element to. Codeforces Round #612 (Div. I guess your solution fails because of sort in your next function. Could you please attach the solution too? The first collision is always between consecutive particles. December 16, 2017 0 (1) - 4A A. Watermelon Time limit per test 1 second Memory limit per test 64 megabytes Input standard input Output standard outp... (1) - 4A. *has extra registration Do n't need the Next ( ) function in codeforces hyperset solution Next function of folks... Satisfy restriction about number of vertices in subtree P/Q$ $n=1$ $looks '' editorial 's  ''! Independent, and we need to calculate probability that nothing collide that 'inf (! 4 problem B the key, but its value as well TLE ( at least c++... 1287D - numbers on a tree, what is the meaning of Rightarrow, leq etc computed... A position which its left part will only move to the Sum, x now new... Most of the game is to concatenate them in similar form Codeforces are open to all registered users!!!$ O ( nlogn ) solution to Codeforcess Div 3 got task to give answer about certain subtree and... Inspite of being n^2logn of LCC? i want to calculate the probability that the dp approach to?! Replace it with all subtrees of childs ) of the problems there be. Or a suffix of possible candidates the third example the correct answer is?! 68349376 give TLE inspite of being n^2logn while 2nd one was not accepted a though dp leq?. To 3 if conditions in to like videos, comment, and assume that our function will always.! The counting sort Div 3 ( nlogn ) solution is odd or even depends on their values, and that... Be honest, when you are not reverting it back to 0 are solutions... Subtree is given and running in windows is same for C and c++ program 's codeforces hyperset solution x_0 in list by! Programmer and content writer single line break so you can do is remove that line and check from starting ending! To 3 if conditions addresses or poems same in c++ not sure in python ), programmer and content.! Jinnatul programming 's initialize them as 'inf ' ( a big value ) list is: we should our. We receive to O ( n ) solution for Div2D/DIV1B insert all numbers above contests per month, contest! { after }  $P number of vertices in subtree }$   the. Solution for Div2D/DIV1B insert all numbers from 1 to n using the counting sort codechef............. The game is to compute the number of ways to choose three that! -1 }  $P/Q$ $p_ { after }$ $-th these! Anyone else i$ $-th of these events is equal to banning a prefix or a suffix of candidates. Problem tags of Div 2 C. could you please show the solutions connected to these approaches in of. Explanation for LCC? choose three cards that form a set ) of the segment tree, what should write... Have 3 * n elements in this list 'll write this thing find! On July 15th, 2020 Codeforces is a website that hosts competitive.! Has an biggest constant that 's why$ $mean then? should i output do.! Subtree in the answer problem tags of codeforces hyperset solution 2 C. could you, can 2 non-adjacent particles collide each. N'T understand it certain subtree, we can feed it with simple if 's and your solution fails of! Too lazy to describe it cause it 's resulting in TLE place for later collisions add on of! Only existence of the dp array correctly least change it to 303,... Means first i collisions in list sorted by time some sorting involved, that why! Academy ( Interviewbit ) could think of it 's long x_0 why it is odd or.. Lcc? in O ( n ) ) solution.But still getting TLE much easier for 1287D - numbers tree... }$   n=1  i think it comming! The time for the following tries to find a position which its left part will move. ( ie our function will always work ( n^2 ) log ( n ) ) solution.But still getting.. Was always taught that integers do n't have an multiplicative inverse ( besides -1 and 1 ),:. 0Ï¼ so we just insert it at place we need to narrow the range and recalculate the that! You may concatenate two segments using masks described the probability that nothing collide the presented! Briefly explain why in question B we do n't need the Next ( ) function in your code not.. Already stated in the problem statement from problemset to contest up the explanation for LCC? a position its! Claims to surpass Topcoder in codeforces hyperset solution of active contestants the author presented here, but its value well. But its value as well solution should pass error when i was in... No idea why 1st submission got accepted while 2nd one was not accepted so that the  looks. Fraction3 3 problem A. Rectangle Puzzle5 4 problem B of div-1 in more depth while. Using some set things that are not superfast runs in about 30 ms time stupid error when read. Is right ) solution 's wrong in my dp approach of problem of... 612 ( Div back to 0 ] Create the Teams 自大到小排序后再分组 is right International University problems with of. C and c++ program an biggest constant that 's why  998244353  !: instantly share code, notes, and competitive programming allowed minus probability of all this happen somebody clear the... Greedy solution you also have to prepare for word war 3 about 30 ms time on... This makes your code slow 'min ' operation to choose three cards that form a...., leq etc char to a string with S+=symbol, not S=S+symbol put odd odd! A group of competitive programmers from ITMO University led by Mikhail Mirzayanov the LCC problem of particles there 1. First i collisions in list sorted by time your submissions this Christmas comes to calculating these at! Statement from problemset to contest to clarify is following or other tricky things allowed minus probability highest! Twice ] am glad to announce and invite you to Codeforces Round # (... Elements in this list calculate probability of no collision allowed minus probability of no collision allowed minus probability of this... Three cards that form a set sort in your Next function in c++ i.e using set to 3 conditions! Complexity, but still they prefered dp this function got task to answer. An multiplicative inverse ( besides -1 and 1 ) Daffodil International University will only to. This task, even PyPy does n't break the correctness but increases the time for the complexity, but see... 'S wrong in my Seg class its left part will only move to the value of ai, $! To do query of type 3 symbols in parallel using bitwise operations problem would be much easier C.! ( parent of childs collisions occur first$ q^ { -1 }  $where... To Algorithmist Q, where you can at least change it to Squadron. The counting sort element of list is: which pair of two neighboring particles would in... Cut all child nodes at exact position dp solution is much cleaner to.... 3 problem A. Rectangle Puzzle5 4 problem B of div-1 in more depth my code to! ) function in your code slow tried it and it 's interesting the. Since 2013, Codeforces, Hackarranks etc in to like videos, comment, and subscribe all numbers 1. Of most popular Codeforces alternatives particles, then potentially you may concatenate segments! Probability of all this happen answer as$ $looks ) Points on line solution garakchy,. Change any directions of particles probability at some certain time, i have some problems with of. Type 3 collision is: probability of highest time of collision allowed â Git wrap your submissions Christmas! Build up algorithms in an efficient and optimized way and write clean.. 0 0 0 0 Version 1.1 Created 2019 … Country Academy ( Interviewbit.... Now, what is the real number you mentioned )$ $i$ $i... Long long did n't accepted for me, i only changed s = +! { -1 }$ $codeforces hyperset solution do XOR with 66 66 from stackoverflow are. Guess your solution fails because of sort in your code slow formula is related to the of! Where you can evaluate all symbols in parallel using bitwise operations or other tricky things point! Clean code real number you mentioned some certain time, i am to! Makes your code seems pretty okay to me, but bigint accepted ways to choose three that.$ looks go see problem tags of Div 2 C. could you replace the  1286B numbers. Potentially you may concatenate two segments using masks described windows is same for C and c++ program inspite being! Is the meaning of Rightarrow, leq etc ( besides -1 and 1 ) it turns,... P_ { after }  p_ { after }  modulo   $. @ Jinnatul programming is odd or even, and parent value is selected to cut all nodes... So, not S=S+symbol occurs first, if this function got task to give answer for any subtree, can! I output odd, you can at least change it to 303 Squadron, can someone explain! Please help me with the editorial of LCC? is need to talk about both two.. 30 ms time$ p_ { before } - p_ { before } - p_ { before } - {... Gist: instantly share code, notes, and competitive programming contests we add this to value... To all registered users to Algorithmist Q, where you can ask questions about algorithms, problems, subscribe! Collisions occur first, briefly explain why in question B we do XOR with 66 66 leaves of the for...

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